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Configuration = 50
cycles = (10 5 3 7 4)(9 6 1 8 2)

a = 5, b = 7, c = 10
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cycles = (10 4)(9 1 6 2 7)(8)(5 3)

a = 1, b = 6, c = 9
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cycles = (10 7)(9 5 2)(8 6)(4)(3)(1)

a = 7, b = 8, c = 10
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cycles = (10 6 7)(9)(8 5 2)(4)(3)(1)

a = 6, b = 7, c = 10
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cycles = (10)(9)(8)(7 5 2)(6)(4)(3)(1)